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Sagot :
The probability that atleast one ticket labeled 2-6 is drawn is 0.94
Numbered ticket = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
Number of draws = 4
Required picks = {2, 3, 4, 5, 6}
Recall :
- Probability = required outcome / Total possible outcomes
Probability of choosing a required ticket :
- 5/10 = 1/2
Therefore, the probability that none of the required tickets is chosen :
- (1/2 × 1/2 × 1/2 × 1/2) = 1/16
The probability that atleasr one ticket labeled 2-6 is drawn is :
1 - P(none is chosen) = 1 - 1/16 = 15/16 = 0.9375
Learn more :https://brainly.com/question/18405415
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