## Answer :

The **probability**** **that **atleast**** **one ticket labeled 2-6 is drawn is **0.94**

Numbered ticket = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

Number of draws = 4

Required picks = {2, 3, 4, 5, 6}

__Recall____ ____:__

*Probability**=**required**outcome**/**Total possible**outcomes*

__Probability____ ____of____ ____choosing a____ ____required____ ____ticket____ ____:__

- 5/10 = 1/2

Therefore, the **probability**** **that none of the required tickets is chosen :

- (1/2 × 1/2 × 1/2 × 1/2) =
**1/16**

The **probability**** **that atleasr one ticket labeled 2-6 is drawn is :

1 - P(none is chosen) = 1 - 1/16 = **15****/****16**** ****=**** ****0.9375**

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