Johnmiedema.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

## Sagot :

__Density = mass / volume__So in order calculate the density of the unknown liquid, we need to know

its mass and its volume.

If the mass of the beaker is 165 grams empty and 309 grams with

something in it, then the mass of the stuff in it must be

(309 - 165) = 144 grams.

The question tells us that its volume is 125 mL (same as 125 cm³),

so we have everything we need.

Density = mass/volume = 144/125 = 1.152 grams per cm³ .

The density of pure water is 1.000 gram per cm³ , so the unknown liquid

is definitely not pure water.

The density of this unknown liquid is 15.2% more than that of pure water.

Even if water had a huge amount of pollution and junk in it, its density

would probably not be that much greater than 1.000 . So the unknown

liquid is probably not polluted water either.

Mass of the liquid = total mass of beaker and liquid inside the beaker -

mass of empty beaker

= 309 grams - 165 grams

= 144 grams

volume of unknown liquid = 125 ml given

Density = mass / volume = 144 / 125 = 1.152 gm / ml