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## Sagot :

I'm about to describe is the easier way.

Probability = (number of successful outcomes)/(total number of possible outcomes)

*How many total pairs can be drawn from 8 total pens ?*-- The first one drawn can be any one of 8 pens. For each of these . . .

-- The second one drawn can be any one of the remaining 7 .

-- Total number of ways of drawing a pair = (8 x 7) = 56 ways.

-- But there aren't 56 different different pairs. Whether you draw A and then B,

or B and then A, you wind up with the same pair. There are 2 different ways to

draw each pair, so the 56 ways of drawing a pair only produces

**different pairs.**

__28__

__How many pairs are two of the same color ?__

*Possible number of blue pairs:*The reasoning is exactly the same as calculating the TOTAL number of

pairs, as explained above.

With 5 blue pens, you can make

**different pairs.**

__10__AB, AC, AD, AE, BC, BD, BE, CD, CE, and DE.

*Possible number of red pairs:*The reasoning is exactly the same as calculating the TOTAL number of

pairs, as explained above.

With 3 red pens, you can make

**different pairs.**

__3__AB, AC, and BC.

Total number of possible same-color pairs = 10 + 3 =

**13**

successes / total possible outcomes = 13/28 =

**(rounded)**

__46.4__%