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## Sagot :

sum of above (a-1)+(a)+(a+1) = 237

3a = 237

a = 79

therefore three numbers are = 78, 79,80

x + (x+1) + (x+2) = 237

3x + 3 = 237

3x = 234

x = 234 / 3 = 78

Therefore the numbers are x (78), x+1 (79) and x+2 (80)