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## Sagot :

[tex]\[ KE = \frac{1}{2} m v^2 \][/tex]

Here's a step-by-step solution:

1.

**Identify the given values:**

- Mass ([tex]\( m \)[/tex]) of Kyle is [tex]\( 54 \, \text{kg} \)[/tex].

- Velocity ([tex]\( v \)[/tex]) of Kyle is [tex]\( 3 \, \text{m/s} \)[/tex].

2.

**Substitute the values into the kinetic energy formula:**

[tex]\[ KE = \frac{1}{2} \times 54 \, \text{kg} \times (3 \, \text{m/s})^2 \][/tex]

3.

**Calculate the square of the velocity:**

[tex]\[ (3 \, \text{m/s})^2 = 9 \, \text{m}^2/\text{s}^2 \][/tex]

4.

**Multiply the mass by the squared velocity:**

[tex]\[ 54 \, \text{kg} \times 9 \, \text{m}^2/\text{s}^2 = 486 \, \text{kg} \cdot \text{m}^2/\text{s}^2 \][/tex]

5.

**Multiply by [tex]\( \frac{1}{2} \)[/tex]:**

[tex]\[ KE = \frac{1}{2} \times 486 \, \text{kg} \cdot \text{m}^2/\text{s}^2 = 243 \, \text{J} \][/tex]

Therefore, Kyle's kinetic energy is [tex]\( 243 \, \text{J} \)[/tex].

The correct answer is [tex]\(\boxed{243 \, \text{J}}\)[/tex].