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## Sagot :

At STP, which is defined by a temperature of 273.15 K (0°C) and a pressure of 1 atm, one mole of an ideal gas occupies a volume of 22.4 liters, which is equivalent to 22,400 milliliters (mL).

Given:

- Number of moles of methane gas (n) = 0.5 moles

- Volume occupied by 1 mole of gas at STP = 22,400 mL

To find the volume occupied by 0.5 moles of methane gas, we can use the following proportional relationship:

[tex]\[ \text{Volume of gas} = \text{Number of moles} \times \text{Volume occupied by one mole} \][/tex]

Plugging in the values:

[tex]\[ \text{Volume of gas} = 0.5 \, \text{moles} \times 22,400 \, \text{mL/mole} \][/tex]

Perform the multiplication:

[tex]\[ \text{Volume of gas} = 11,200 \, \text{mL} \][/tex]

Therefore, 0.5 moles of methane gas at STP occupies a volume of 11,200 mL.