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## Sagot :

[tex]55+45+28+7=135\\\\ \boxed{135=135}[/tex]

**Jane **has $55, **Bill **has $45, Tricia has $28, and **Steve **has $7.

Given that

**Jane **has $10 more than Bill, **Bill **has $17 more than Tricia, and **Tricia **has $21 more than **Steve**.

If the total **amount **of all their **money **is $135.

We have to **determine**

How much **money **does each have?

**According **to the **question**

Let the amount **Steve **be **x**,

The total amount **Jane **has is (10 +17+21+x)

The total amount **Bill **has is (17+21+x)

The total amount **Tricia **has is (21+x)

Then,

The total **amount **of all **money **= Jane money + Bill money + Tricia money + Steve money

[tex]\rm 135 =( 10+17+21+x)+ (17+21+x) + (21+x)+x\\\\135 = 48+x + 38+x+21+x+x\\\\135 = 4x+ 107\\\\4x = 135-107\\\\4x = 28\\\\ x = \dfrac{28}{4}\\\\ x= 7[/tex]

The **Steve **has $7.

Therefore,

The total money **Jane **has = (10 +17+21+x) = 48 + 7 = $55

The total money **Bill **has = (17+21+x) = 38 +7 = $45

The total money **Tricia **has = (21+x) = 21 +7 = $28

Hence, **Jane **has $55, **Bill **has $45, Tricia has $28, and **Steve **has $7.

To know more about **Equation **click the link given below.

https://brainly.com/question/14454996