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Given:

[tex]\sin 285^{\circ}[/tex]To express it as a function of reference angle:

Since the angle lies in the fourth quadrant.

So, the reference angle will be,

[tex]\begin{gathered} \theta_{ref}=360-\theta_4 \\ \theta_{ref}=360^{\circ}-285 \\ \theta_{ref}=75^{\circ} \end{gathered}[/tex]**Therefore, the function of the reference angle is,**