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WRITE AN EQUATION IN SLOPE INTERCEPT FORM OF THE LINE THAT PASSES THROUGH THE GIVEN POINT AND IS PARALLEL TO THE GRAPH OF THE GIVEN EQUATION (2,-2):Y=-X-2 I HAVE NO IDEA. I AM STRUGGLING SO BAD WITH THIS

Sagot :

Okay, let's start with the given equation.
y=-x-2
The slope of that line would be -1
A line parallel to this would have the same slope of -1
Slope intercept form is y=mx+b
"m" is the slope and "b" is the y-intercept.
Substitute the given x and y values from the given point and the slope into this equation.
x=2, y=-2, m=-1 and we are solving for b
You then have:
-2=-1(2) + b
-2 = -2 + b
b= 0
Now, we have the y-intercept and the slope, which is all we need to create the equation
b=0, m=-1
Final answer: y=-x + 0 :)