At Johnmiedema.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

## Sagot :

**Answer****:**

EDF = 70°

**Explanation****:**

m∠DBC = 180° - 125° = 55°

**As its a isosceles triangle, it has two equal or same angles.**

Find m∠BDC = 180° - 55° - 55° = 70°

EDF is parallel to BDC.

m∠EDF = 70°

**Answer:**

70º

**Step-by-step explanation:**

We know that ∠ABD=125º. We also can see that ∠ABD and ∠DBC are supplementary. So, ∠DBC=180º-125º=55º. Now, that we know ∠DBC=55º we can find out that ∠BCD also is 55º because the triangle is isosceles. ∠DBC, ∠BCD, and ∠BDC are in a triangle, so their sum is 180º. So, ∠DBC=180º-55º-55º=70º. Now, that we know ∠DBC=70º we can find out ∠EDF because the two are vertical angles. ∠DBC=∠EDF=70º.